Housework: The Key To All Successful Relationships Essay

When thinking of the term housework, even in today’s evolved society, it is sometimes known to be an activity that females in the family are generally responsible for. However, housework is not only defined by cleanliness and tidiness of a home, but also includes the up-keep, and maintenance. These are essential in order to keep the house in good condition. In my family, the men have become mainly in charge of the maintenance and women in charge of cleanliness. Housework should not be reserved for one gender, but rather combined by both genders. The break down of roles between genders will allow for better relationships in life. The act of housework can become a large issue in a home that does not have structure and specific roles. Growing up, my dad was away most of week and frequently went on long trips during hockey season, and the winter months. My mom played both roles of mom and dad while he was away. In the past, my mom has expressed over, and over again that she is tir ed of cleaning other people’s messes and trying to maintenance everything herself. We would argue constantly about not picking up after ourselves, and leaving all the chores for mom. About 6 years ago we realized that it is very unfair, as well as time consuming, for my mom to be in charge of getting everything done. As we grow older, it seems that there is more laundry, dirty dishes, and things that need to be fixed. We decided to be consistent with cleaning, and managing the house as a family. Our relationships have been almost amazing ever since. As I have mentioned, housework involves both the cleanliness and up-keep of a home. In our family, we’ve found that the best way to get things done is to know our strengths and weaknesses, and divide up the work accordingly. My dad and brother are responsible for vacuuming, fixing things that are broken, cutting the grass, taking out the garbage, and most of the outdoor work that is commonly known as manly tasks. My mom and I are responsible for the dishes, laundry, and keeping the house tidy inside. We all help out with the preparation of meals whether it be setting the table, cutting up vegetables, or actually doing the cooking. We do switch roles sometimes, but mostly stick with what we are good at, or don’t mind doing. The routine  and contribution to housework from all of our family members has really changed the mood in the house over the passed 6 years. Just like finances can sometimes have a bad impact on a relationship or marriage, not contributing or working as a team to keep the place we call home in good order; can also impact a family for the worst. Working well with others and being a team player are skills that become very important as people grow up. They are skills that teach us to communicate, and be considerate. Growing children of both genders must learn balance, teamwork, and the importance of contribution. Being able to practice these skills in our home since a young age has helped my brother and I to bring the things we have learned into the real world. I have heard that boys who grow up with sisters do not usually get asked as often to do housework by their parents, and subsequ ently do not end up contributing later on in life. That was not the case in my home, and to be honest, I am very thankful! Once we decided as a family that we would all contribute, we made sure that we stuck to it. Working as a team has personally helped me become an all around good worker, no matter what job has come my way. I’ve learned to consider and respect others opinions as well as communicate well with co-workers and any employer that I have worked for. For the passed three years, I have lived with two other roommates while going to school in Ottawa. Thanks to everything that I learned about contribution at home, I have made sure to make a good effort in doing my part, and cleaning up after myself at our house in Ottawa. I plan to live with my boyfriend within the next year, and it is nice to know that he was brought up the same way as I was. We have both learned the importance of contribution in a relationship. Housework and contribution cannot solely be in the hands of one gender or another. It takes a combined effort to make a household, and relationships in life run smoothly. Relationships that include roles that are shared, and consideration that is given towards others, help avoid issues that arise from lack of contribution. Children that come from homes that make sure to divide up the work between family members also learn balance, teamwork, and the importance of contribution. These skills are important for everyone to obtain, and ensure good relationships throughout life.

Experiment 1: Calorimetry

Experiment 1: Calorimetry Nadya Patrica E. Sauza, Jelica D. Estacio Institute of Chemistry, University of the Philippines, Diliman, Quezon City 1101 Philippines Results and Discussion Eight Styrofoam ball calorimeters were calibrated. Five milliliters of 1M hydrochloric acid (HCl) was reacted with 10 ml of 1M sodium hydroxide (NaOH) in each calorimeter. The temperature before and after the reaction were recorded; the change in temperature (? T) was calculated by subtracting the initial temperature from the final temperature. The reaction was performed twice for every calorimeter. The heat capacity (Ccal) of each calorimeter was calculated using the formula, C_cal=(- H? _rxn^o n_LR)/? T[1] where ? Horxn is the total heat absorbed or evolved for every mole of reaction and nLR is the number of moles of the limiting reactant. The ? Horxn used was -55. 8kJ per mole of water while the nLR was 0. 005 mole. Table 1. Average Ccal from recorded ? T values. Trial? T, (oC)Ccal, (J)Ave Ccal, (J) 112. 2126. 82202. 91 21. 0279. 00 213. 093. 00108. 50 22. 3124. 00 310. 5558. 00558. 00 20. 5558. 00 412. 0139. 50244. 13 20. 8348. 75 513. 093. 0081. 38 24. 069. 75 612. 0139. 50209. 25 21. 0279. 00 712. 111. 60111. 60 22. 5111. 60 813. 093. 00116. 25 22. 0139. 50 Different heat capacities were calculated for each calorimeter (Table 1). After calibration, a reaction was performed in a calorimeter by each pair. A total of eight reactions were observed by the whole class. The temperature before and after the reaction were recorded. Then the change in temperature was calculated. Eac h reaction was performed twice to produce two trials. The experimental ? Horxn for each reaction was solved using the formula, H? _rxn^o=(-C_cal ? T)/n_LR [2] where Ccal is the heat capacity previously calculated for each calorimeter. The percent error for each reaction was computed by comparing the computed experimental ? Horxn to the theoretical ? Horxn using the formula, % error=|(computed-theoretical)/theoretical|? 100% [3] Table 2. Comparison of calculated ? Horxn and theoretical ? Horxn. RxnLRTrial? T, (oC)? Horxn, (kJ/mol)Ave ? Horxn, (kJ/mol)Theo ? Horxn, (kJ/mol)% Error 1HCl13. 5-142. 04-131. 89-132. 510. 47 23. 0-121. 75 2HOAc11. 3-26. 34-41. 61-56. 0924. 65 22. 7-56. 89 3HOAc11. 8-189. 61-203. 16-52. 47287. 18 22. 0-216. 70 4HNO311. 5-73. 24-70. 80-55. 8426. 78 21. 4-68. 36 5Mg13. 0-118. 67-138. 45-466. 8570. 34 24. 0-158. 23 6Mg15. 5-559. 4-635. 72-953. 1133. 30 27. 0-712. 01 7Zn13. 0-43. 80-43. 80-218. 6679. 97 23. 0-43. 80 8CaCl210. 00. 00-5. 8113. 07144. 47 20. 5-11. 63 There were differences in experimental and theoretical values of ? Horxn as shown by the percent error for each reaction (table 2). The discrepancies were caused by many factors. One factor was the loss of heat. The heat may have bee n released when the thermometer was pushed or pulled during the reaction. The heat may also have been lost because the calorimeter is not totally isolated. Another factor was the dilution of the solution. The pipette or test tube may still have been wet when used. However, the concentration used in solving for values was the concentration of the undiluted solution. Another factor that may have contributed to the difference in the experimental and theoretical values was human error. It was manifested when reading the thermometer or measuring chemicals with different instruments. The factors aforementioned are the limitations of this experiment. References Petrucci, R. H. ; Herring, F. G. ; Madura, J. D. ; Bissonnette, C. General Chemistry, 10th ed. ; Pearson Education: Canada, 2011; Chapter 7. Appendices Appendix A Comparison of Observed and Theoretical Heats of Reactions RxnLRTrial? TnLRqrxn? HorxnAve ? HorxnTheo ? Horxn% Error 1HCl13. 500. 00500-710. 19-142. 04-131. 89-132. 510. 47 23. 000. 00500-608. 73-121. 75 2HOAc11. 250. 00515-135. 63-26. 34-41. 61-56. 0924. 65 22. 700. 00515-292. 95-56. 89 3HOAc11. 750. 00515-976. 50-189. 61-203. 16-52. 47287. 18 22. 000. 00515-1116. 00-216. 70 4HNO311. 500. 00500-366. 19-73. 24-70. 80-55. 8426. 78 21. 400. 00500-341. 78-68. 36 5Mg13. 000. 00206-244. 13-118. 67-138. 45-466. 8570. 34 24. 000. 00206-325. 50-158. 23 6Mg15. 500. 00206-1150. 88-559. 44-635. 72-953. 1133. 30 27. 000. 00206-1464. 75-712. 01 7Zn13. 000. 00764-334. 80-43. 80-43. 80-218. 6679. 97 23. 000. 00764-334. 80-43. 0 8Na2CO3/ CaCl210. 000. 005000. 000. 00-5. 8113. 07144. 47 20. 500. 00500-58. 13-11. 63 Appendix B Sample Calculations Calibration of Calorimeter 10ml 1M NaOH + 5ml 1M HCl n. i. e. : OH-(aq) + H+(aq) ? H2O(l)? Horxn= -55. 8kJ LR: HCLnLR= 0. 005mol Grp 1 Trial 1 ?T= 2. 2oC Sol’n: C_cal=(- H? _rxn^o n_LR)/? T C_cal=(-(-55. 8kJ)(0. 005mol))/(? 2. 2? ^ o C)? 1000J/1kJ ?(C_cal=126. 82 J) Determination of Heats of Reaction Neutralization Reaction Rxn 4 Trial 1: 10ml 1M NaOH + 5ml 1M HNO3 n. i. e. : OH-(aq) + H+(aq) ? H2O(l) LR: HNO3nLR= 0. 005mol ?T= 1. 5oCCcal= 244. 125 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(244. 25J)(? 1. 5? ^o C))/0. 005mol? 1kJ/1000J ? ( H? _rxn^o=-73. 24kJ) Reaction between an Active Metal and an Acid Rxn 5 Trial 1: 15ml 1M HCl+ 0. 05g Mg n. i. e. : 2H+(aq) + Mg(s) ? Mg+2(aq) + H2(g) LR: MgnLR= 0. 00206mol ?T= 3oCCcal= 81. 375 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(81. 375J)(3^o C))/0. 00206mol? 1kJ/1000J ?( H? _rxn^o=-118. 67kJ) Displacement of One Metal by Another Rxn 7 Trial 1: 15ml 1M CuSO4 + 0. 5g Zn n. i. e. : Cu+2(aq) + Zn(s) ? Zn+2(aq) + Cu(s) LR: ZnnLR= 0. 00764mol ?T= 3oCCcal= 111. 6 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(111. 6J)(3^o C))/0. 00764mol? 1kJ/1000J ?( H? rxn^o=-43. 80kJ) Precipitation Reaction Rxn 8 Trial 1: 10ml 0. 5M Na2CO3 + 5ml 1M CaCl2 n. i. e. : CO3-2(aq) + Ca+2(aq) ? CaCO3(s) LR: Na2CO3/ CaCl2nLR= 0. 005mol ?T= 0. 5oCCcal= 116. 25 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(116. 25J)(? 0. 5? ^o C))/0. 005mol? 1kJ/1000J ? ( H? _rxn^o=-11. 63kJ) Appendix C Answers to the Questions in the Lab Manual There are many possibilities that explain the discrepancy of the experimental and theoretical values of ? Horxn. First, heat might have been lost to the surroundings. This is possible whenever the thermometer is pulled out or pushed in the calorimeter during the reaction. Also, the calorimeter might not have been thoroughly isolated. Second, the solution might have been diluted in the test tube or pipette. They might have been wet when used with the solution. Lastly, the discrepancies might have occurred due to human error. The students might have misread the thermometer when taking the temperature or the pipette when measuring the solutions. a. It is important to keep the total volume of the resulting solution to 15ml because any more or any less than that of the volume can contribute to the absorption or release of additional heat therefore affecting the ? Horxn. b. It is important to know the exact concentrations of the reactants to solve for their number of moles and to find out the limiting reactant. c. It is important to know the exact weight of the metal solids used to solve for their number of moles and to find out whether one of them is a limiting reactant. Also, the weight is needed to solve for the heat capacity of the solid when the specific heat is given. 200ml 0. 5M HA + NaOH ? -6. 0kJ LR: HAnLR= 0. 1mole H? _(rxn,mol)^o= (-6. 0 kJ)/(0. 1 mol) ?( H? _(rxn,mol)^o= -60 kJ) HA is a strong acid. OH-(aq) + H+(aq) ? H2O(l)? Horxn= -60 kJ/mole Calibration:15ml 2. M HCl + 5ml 2. 0M NaOH? T=5. 60oC LR: NaOHnLR= 0. 01mole Reaction:20ml 0. 450M CuSO4 + 0. 264g Zn? T=8. 83oC LR: ZnnLR= 0. 00404mole n. i. e. : OH-(aq) + H+(aq) ? H2O(l) n. i. e. : Cu+2(aq) + Zn(s) ? Zn+2(aq) + Cu(s) C_cal=(- H? _rxn^o n_LR)/? T C_cal=(-(-55. 8kJ)(0. 01mol))/(? 5. 60? ^o C)? 1000J/1kJ ?(C_cal=99. 6 J) H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(99. 6J)(? 8. 83? ^o C))/0. 00404mol? 1kJ/1000J ? ( H? _rxn^o=-218. 0 kJ) OH-(aq) + H+(aq) ? H2O(l)? Horxn= -55. 8kJ ?Hof,H2O= -285 kJ ?Hof,OH-= ? ?Horxn= ? Hof,product – ? Hof,reactant -55. 8 kJ = ? Hof,OH- – (-285 kJ) ?( H? _(f,? OH? ^-)^o=-218. 0 kJ) Experiment 1: Calorimetry Experiment 1: Calorimetry Nadya Patrica E. Sauza, Jelica D. Estacio Institute of Chemistry, University of the Philippines, Diliman, Quezon City 1101 Philippines Results and Discussion Eight Styrofoam ball calorimeters were calibrated. Five milliliters of 1M hydrochloric acid (HCl) was reacted with 10 ml of 1M sodium hydroxide (NaOH) in each calorimeter. The temperature before and after the reaction were recorded; the change in temperature (? T) was calculated by subtracting the initial temperature from the final temperature. The reaction was performed twice for every calorimeter. The heat capacity (Ccal) of each calorimeter was calculated using the formula, C_cal=(- H? _rxn^o n_LR)/? T[1] where ? Horxn is the total heat absorbed or evolved for every mole of reaction and nLR is the number of moles of the limiting reactant. The ? Horxn used was -55. 8kJ per mole of water while the nLR was 0. 005 mole. Table 1. Average Ccal from recorded ? T values. Trial? T, (oC)Ccal, (J)Ave Ccal, (J) 112. 2126. 82202. 91 21. 0279. 00 213. 093. 00108. 50 22. 3124. 00 310. 5558. 00558. 00 20. 5558. 00 412. 0139. 50244. 13 20. 8348. 75 513. 093. 0081. 38 24. 069. 75 612. 0139. 50209. 25 21. 0279. 00 712. 111. 60111. 60 22. 5111. 60 813. 093. 00116. 25 22. 0139. 50 Different heat capacities were calculated for each calorimeter (Table 1). After calibration, a reaction was performed in a calorimeter by each pair. A total of eight reactions were observed by the whole class. The temperature before and after the reaction were recorded. Then the change in temperature was calculated. Eac h reaction was performed twice to produce two trials. The experimental ? Horxn for each reaction was solved using the formula, H? _rxn^o=(-C_cal ? T)/n_LR [2] where Ccal is the heat capacity previously calculated for each calorimeter. The percent error for each reaction was computed by comparing the computed experimental ? Horxn to the theoretical ? Horxn using the formula, % error=|(computed-theoretical)/theoretical|? 100% [3] Table 2. Comparison of calculated ? Horxn and theoretical ? Horxn. RxnLRTrial? T, (oC)? Horxn, (kJ/mol)Ave ? Horxn, (kJ/mol)Theo ? Horxn, (kJ/mol)% Error 1HCl13. 5-142. 04-131. 89-132. 510. 47 23. 0-121. 75 2HOAc11. 3-26. 34-41. 61-56. 0924. 65 22. 7-56. 89 3HOAc11. 8-189. 61-203. 16-52. 47287. 18 22. 0-216. 70 4HNO311. 5-73. 24-70. 80-55. 8426. 78 21. 4-68. 36 5Mg13. 0-118. 67-138. 45-466. 8570. 34 24. 0-158. 23 6Mg15. 5-559. 4-635. 72-953. 1133. 30 27. 0-712. 01 7Zn13. 0-43. 80-43. 80-218. 6679. 97 23. 0-43. 80 8CaCl210. 00. 00-5. 8113. 07144. 47 20. 5-11. 63 There were differences in experimental and theoretical values of ? Horxn as shown by the percent error for each reaction (table 2). The discrepancies were caused by many factors. One factor was the loss of heat. The heat may have bee n released when the thermometer was pushed or pulled during the reaction. The heat may also have been lost because the calorimeter is not totally isolated. Another factor was the dilution of the solution. The pipette or test tube may still have been wet when used. However, the concentration used in solving for values was the concentration of the undiluted solution. Another factor that may have contributed to the difference in the experimental and theoretical values was human error. It was manifested when reading the thermometer or measuring chemicals with different instruments. The factors aforementioned are the limitations of this experiment. References Petrucci, R. H. ; Herring, F. G. ; Madura, J. D. ; Bissonnette, C. General Chemistry, 10th ed. ; Pearson Education: Canada, 2011; Chapter 7. Appendices Appendix A Comparison of Observed and Theoretical Heats of Reactions RxnLRTrial? TnLRqrxn? HorxnAve ? HorxnTheo ? Horxn% Error 1HCl13. 500. 00500-710. 19-142. 04-131. 89-132. 510. 47 23. 000. 00500-608. 73-121. 75 2HOAc11. 250. 00515-135. 63-26. 34-41. 61-56. 0924. 65 22. 700. 00515-292. 95-56. 89 3HOAc11. 750. 00515-976. 50-189. 61-203. 16-52. 47287. 18 22. 000. 00515-1116. 00-216. 70 4HNO311. 500. 00500-366. 19-73. 24-70. 80-55. 8426. 78 21. 400. 00500-341. 78-68. 36 5Mg13. 000. 00206-244. 13-118. 67-138. 45-466. 8570. 34 24. 000. 00206-325. 50-158. 23 6Mg15. 500. 00206-1150. 88-559. 44-635. 72-953. 1133. 30 27. 000. 00206-1464. 75-712. 01 7Zn13. 000. 00764-334. 80-43. 80-43. 80-218. 6679. 97 23. 000. 00764-334. 80-43. 0 8Na2CO3/ CaCl210. 000. 005000. 000. 00-5. 8113. 07144. 47 20. 500. 00500-58. 13-11. 63 Appendix B Sample Calculations Calibration of Calorimeter 10ml 1M NaOH + 5ml 1M HCl n. i. e. : OH-(aq) + H+(aq) ? H2O(l)? Horxn= -55. 8kJ LR: HCLnLR= 0. 005mol Grp 1 Trial 1 ?T= 2. 2oC Sol’n: C_cal=(- H? _rxn^o n_LR)/? T C_cal=(-(-55. 8kJ)(0. 005mol))/(? 2. 2? ^ o C)? 1000J/1kJ ?(C_cal=126. 82 J) Determination of Heats of Reaction Neutralization Reaction Rxn 4 Trial 1: 10ml 1M NaOH + 5ml 1M HNO3 n. i. e. : OH-(aq) + H+(aq) ? H2O(l) LR: HNO3nLR= 0. 005mol ?T= 1. 5oCCcal= 244. 125 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(244. 25J)(? 1. 5? ^o C))/0. 005mol? 1kJ/1000J ? ( H? _rxn^o=-73. 24kJ) Reaction between an Active Metal and an Acid Rxn 5 Trial 1: 15ml 1M HCl+ 0. 05g Mg n. i. e. : 2H+(aq) + Mg(s) ? Mg+2(aq) + H2(g) LR: MgnLR= 0. 00206mol ?T= 3oCCcal= 81. 375 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(81. 375J)(3^o C))/0. 00206mol? 1kJ/1000J ?( H? _rxn^o=-118. 67kJ) Displacement of One Metal by Another Rxn 7 Trial 1: 15ml 1M CuSO4 + 0. 5g Zn n. i. e. : Cu+2(aq) + Zn(s) ? Zn+2(aq) + Cu(s) LR: ZnnLR= 0. 00764mol ?T= 3oCCcal= 111. 6 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(111. 6J)(3^o C))/0. 00764mol? 1kJ/1000J ?( H? rxn^o=-43. 80kJ) Precipitation Reaction Rxn 8 Trial 1: 10ml 0. 5M Na2CO3 + 5ml 1M CaCl2 n. i. e. : CO3-2(aq) + Ca+2(aq) ? CaCO3(s) LR: Na2CO3/ CaCl2nLR= 0. 005mol ?T= 0. 5oCCcal= 116. 25 J Sol’n H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(116. 25J)(? 0. 5? ^o C))/0. 005mol? 1kJ/1000J ? ( H? _rxn^o=-11. 63kJ) Appendix C Answers to the Questions in the Lab Manual There are many possibilities that explain the discrepancy of the experimental and theoretical values of ? Horxn. First, heat might have been lost to the surroundings. This is possible whenever the thermometer is pulled out or pushed in the calorimeter during the reaction. Also, the calorimeter might not have been thoroughly isolated. Second, the solution might have been diluted in the test tube or pipette. They might have been wet when used with the solution. Lastly, the discrepancies might have occurred due to human error. The students might have misread the thermometer when taking the temperature or the pipette when measuring the solutions. a. It is important to keep the total volume of the resulting solution to 15ml because any more or any less than that of the volume can contribute to the absorption or release of additional heat therefore affecting the ? Horxn. b. It is important to know the exact concentrations of the reactants to solve for their number of moles and to find out the limiting reactant. c. It is important to know the exact weight of the metal solids used to solve for their number of moles and to find out whether one of them is a limiting reactant. Also, the weight is needed to solve for the heat capacity of the solid when the specific heat is given. 200ml 0. 5M HA + NaOH ? -6. 0kJ LR: HAnLR= 0. 1mole H? _(rxn,mol)^o= (-6. 0 kJ)/(0. 1 mol) ?( H? _(rxn,mol)^o= -60 kJ) HA is a strong acid. OH-(aq) + H+(aq) ? H2O(l)? Horxn= -60 kJ/mole Calibration:15ml 2. M HCl + 5ml 2. 0M NaOH? T=5. 60oC LR: NaOHnLR= 0. 01mole Reaction:20ml 0. 450M CuSO4 + 0. 264g Zn? T=8. 83oC LR: ZnnLR= 0. 00404mole n. i. e. : OH-(aq) + H+(aq) ? H2O(l) n. i. e. : Cu+2(aq) + Zn(s) ? Zn+2(aq) + Cu(s) C_cal=(- H? _rxn^o n_LR)/? T C_cal=(-(-55. 8kJ)(0. 01mol))/(? 5. 60? ^o C)? 1000J/1kJ ?(C_cal=99. 6 J) H? _rxn^o=(-C_cal ? T)/n_LR H? _rxn^o=(-(99. 6J)(? 8. 83? ^o C))/0. 00404mol? 1kJ/1000J ? ( H? _rxn^o=-218. 0 kJ) OH-(aq) + H+(aq) ? H2O(l)? Horxn= -55. 8kJ ?Hof,H2O= -285 kJ ?Hof,OH-= ? ?Horxn= ? Hof,product – ? Hof,reactant -55. 8 kJ = ? Hof,OH- – (-285 kJ) ?( H? _(f,? OH? ^-)^o=-218. 0 kJ)

Overview of French Interrogative Adverbs

Overview of French Interrogative Adverbs Interrogative adverbs are used to ask for specific information or facts. As adverbs, they are invariable, meaning they never change form. The most common French interrogative adverbs are: combien, comment,  oà ¹, pourquoi, and quand.  They can be used to ask questions with est-ce que  or subject-verb  inversion  or to pose indirect questions. And some can be worked into to nimporte (no matter)  expressions. 'Combien (de)' Combien means how many or how much. When its followed by a noun, combien requires the preposition de (of).  For example: Combien de pommes est-ce que tu vas acheter ? How many apples are you going to buy?Combien de temps avez-vous  ? How much time do you have 'Comment' Comment means how and sometimes what. For example: Comment va-t-il  ?   How is he doing?Comment as-tu fait à §a  ?   How did you do that?Comment  ?   What?Je ne vous ai pas entendu.   Ã‚  I didn’t hear you.Comment vous appelez-vous ? What’s your name? 'Oà ¹' Oà ¹Ã‚  means where. For example:   Oà ¹ veux-tu manger  ?   Where do you want to eat?Oà ¹ est-ce qu’elle a trouvà © ce sac  ?   Where did she find this bag? 'Pourquoi ' Pourquoi  means why. For example: Pourquoi à ªtes-vous partis  ?   Why did you leave?Pouquoi est-ce qu’ils sont en retard  ?   Why are they late? 'Quand' Quand means when. For example Quand veux-tu te rà ©veiller  ?   When do you want to wake up?Quand est-ce que Paul va arriver  ?   When is Paul going to arrive? In Questions With "Est-Ce Que" or Inversion All of these interrogative adverbs can be used to ask questions with either est-ce que or subject-verb  inversion. For example: Quand manges-tu  ? / Quand est-ce que tu manges  ?   When do you eat?Combien de livres veut-il  ? / Combien de livres est-ce quil veut  ?   How many books does he want?Oà ¹ habite-t-elle  ? / Oà ¹ est-ce quelle habite  ?   Where does she live? In Posing Indirect Questions They can be useful in indirect questions. For example: Dis-moi quand tu manges.   Tell me when you eat.Je ne sais pas combien de livres il veut.   I dont know how many books he wants.Jai oublià © oà ¹ elle habite.   I  forgot where she lives. With 'N'Importe' Expressions Comment, oà ¹, and quand can be used after nimporte  (no matter) to form indefinite adverbial phrases.  For example: Tu peux manger nimporte quand. You can eat whenever / anytime. And the Literary Why: 'Que' In literature or other formal French, you might see an additional interrogative adverb: que, meaning why. For example: Quavais-tu besoin de lui en parler  ? Why did you have to go and talk to him about it?Olivier et Roland, que nà ªtes-vous ici  ? (Victor Hugo) Olivier and Roland, why arent you here?

Physical properties and change essays

Physical properties and change essays A physical change occurs when an object goes through a change that doesnt alter its chemical nature. A physical change involves a change in physical properties. Physical properties can be observed or measured with out changing the type of matter. A physical property doesnt describe a change; it tells what the substance is composed of. Although a physical change doesnt alter the state of the element. There are many parts in a physical change and variables in a physical property. Physical properties can be observed without changing the type of matter. Examples of physical properties include: texture, shape, size, color, odor, volume, mass, weight, and density. An example of a physical change occurs when making a baseball bat. Wood is carefully crafted into a shape which will allow a batter to best apply force on the ball. Even though the wood has changed shape and therefore physical properties, the chemical nature of the wood has not been altered. The bat and the original piece of wood are still the same chemical substance. A physical change is a change in matter that involves no chemical reaction. When a substance undergoes a physical change, the composition of its molecules remains unchanged, and the substance does not lose its chemical identity. Melting, evaporating, and freezing are three types of physical change. For example, water (H2O) is a liquid that freezes to form the solid ice, which may again be melted into water. Because molecules of water and ice are composed of the same chemical elements in the same proportions, the change from water to ice is a physical change. Physical changes include any alteration in the shape and size of a substance. For example cutting, grinding, crushing, annealing, dissolving, or emulsifying produce physical changes. Still another physical change is sublimation, the change from a solid to a gas. According to Reeves physical Changes are those that do not involve changes in ...

Snowy Owl Facts

Snowy Owl Facts Snowy owls (Bubo scandiacus) are the heaviest owls in the United States. They are notable for their striking white plumage and their extreme northerly range which includes tundra habitat throughout Alaska, Canada, and Eurasia. While they are relatively rare, they are often spotted in winter when they hunt in windswept fields or dunes. Fast Facts: Snowy Owl Scientific Name: Bubo scandiacusCommon Names: Arctic owls, great white owls, white owls, Harfangs, American snowy owls, snowy owls, ghost owls, tundra ghosts, ookpiks, ermine owls, Scandinavian nightbirds, and highland tundra owlsBasic Animal Group:  BirdSize: Body: 20 to 28 inches; wingspan: 4.2 to 4.8 feetWeight: 3.5–6.5 poundsLifespan: 10 yearsDiet:  CarnivoreHabitat:  Northern United States, parts of Canada; migration takes them to parts of Europe and AsiaPopulation:  200,000Conservation  Status:  Vulnerable   Description The plumage of an adult male snowy owl is mostly white with few dark markings. Females and young owls have a sprinkling of darker feathers that form spots or bars over their wings, breast, upper parts and the back of their head. This speckling offers superb camouflage and enables juveniles and females to blend well with the summertime colors and textures of the tundras vegetation. During the nesting season, females are often are heavily soiled on their underside from sitting on the nest. Snowy owls have bright yellow eyes and a black bill. Vicki Jauron, Babylon and Beyond Photography / Getty Images Habitat and Distribution Snowy owls range from the western Aleutians in Alaska to northeastern Manitoba, northern Quebec, Labrador, and the northern United States. They are primarily tundra birds although they sometimes also inhabit grasslands. They venture into forests only on very rare occasions, if ever. During the winter, snowy owls often move southward. During their migration, they are sometimes seen along coastlines and lake shores. They sometimes stop at airports, possibly because they offer them the wide-open habitat they prefer. During the breeding season, which snowy owls spend in the Arctic, they nest on small rises in the tundra where the female carves out a scrape or shallow depression in the ground in which to lay her eggs. Snowy owls rely on prey populations that fluctuate significantly over time. As a result, snowy owls are nomadic birds and go wherever there are ample food resources at any particular time. During normal years, snowy owls remain in the northernmost parts of Alaska, Canada, and Eurasia. But in seasons when prey is not abundant in the northern stretches of their range, snowy owls move further southward. Occasionally, snowy owls move to regions that are farther south than their normal range. For example, during the years of 1945 through 1946, snow owls made a widespread, coast-to-coast incursion into the southern stretches of Canada and the northern parts of the United States. Then in 1966 and 1967, snowy owls moved deeply into the Pacific Northwest region. These incursions have coincided with cyclic declines in the lemming population. Diet During the breeding season, snowy owls survive on a diet that consists of lemmings and voles. In parts of their range where lemmings and voles are absent, such as the Shetland Islands, snowy owls feed on rabbits or chicks of wading birds. Behavior Unlike most owls, snowy owls are primarily diurnal birds, usually active during the day, from dawn to dusk. Sometimes snowy owls do hunt at night. It is important to remember that within their Arctic range, snowy owls experience long summer days and hunting at night simply isnt an option as there are few or no hours of darkness. The opposite is true in winter when day length shortens and hunting during daylight hours is reduced or eliminated as the sun remains below the horizon for long stretches of time. Outside the breeding season, snowy owls make very few vocalizations. During the breeding season, snowy owls are a bit more vocal. Males make a barking kre or krek-krek call. Females produce a loud whistling or mewling pyee-pyee or prek-prek sound. Snowy owls also produce a low-pitched hoot that carries through the air for long distances and can be heard as much as 10 kilometers away. Other sounds snowy owls make include hissing, bill snapping and a clapping sound believed to be created by clicking the tongue. Reproduction and Offspring Normally, snowy owls lay between five and eight eggs per clutch. But in good years when prey such as lemmings is abundant, they lay as many as 14 eggs per clutch. Female snowy owls lay their 2.2 inch long eggs at two-day intervals so that the young emerge from the egg at different times. Mud-brown hatchlings emerge from their eggs at about the size of a newly-hatched chicken. Hatchlings in the same nest are of differing ages, with some having hatched as much as two weeks apart. Snowy owl chicks weigh only about 45 grams at birth, but they grow rapidly, gaining about three grams each day. They mature over the course of two years, at which point they weigh approximately 4.5 pounds. Javier Piva Flos/Getty Images   Conservation Status There are approximately 200,000 snowy owls in North America. Despite conservation efforts, these unique owls are now considered to be a vulnerable species. While breeding areas are usually far away from human interference, climate change is impacting the snowy owls Arctic habitat; the number of these birds is on the decline. Relatives of the Horned Owl Until recently, snowy owls were the only member of the genus Nyctea but recent molecular studies showed snowy owls to be close relatives of the horned owls. As a result, taxonomists have moved snowy owls to the genus Bubo. Other members of the genus Bubo include the American horned owls and the Old World eagle-owls. Like other horned owls, snowy owls have ear tufts but they are small and usually kept tucked away. Sources â€Å"Basic Facts About Snowy Owls.†Ã‚  Defenders of Wildlife, 10 Jan. 2019, defenders.org/snowy-owl/basic-facts.â€Å"Snowy Owl.†Ã‚  Audubon, 21 Mar. 2019, www.audubon.org/field-guide/bird/snowy-owl.â€Å"Snowy Owl.†Ã‚  National Geographic, 24 Sept. 2018, www.nationalgeographic.com/animals/birds/s/snowy-owl/.

Employability Skills in Improving Quality of Performance Essay

Employability Skills in Improving Quality of Performance - Essay Example Therefore, team role is â€Å"an inclination to behave, contribute and interrelate with other people in a particular way†, and it measures behavior rather than individuals personally (Belbin 2011). Therefore, we can guarantee that we can use our strengths to our advantage, by discovering our team roles to assist us to manage our weak points. According to Belbin (1981, cited in select knowledge 2001 p.32), there are nine team roles which individuals prefer to assume or avoid when required by circumstances. These team roles consist of Resource Investigator, Coordinator, Monitor Evaluator Team workers, Plant, Implementer, Shaper, Specialist, and Completer Finisher (Belbin 2011). I have experienced some of these roles in my high school study team and in other various tasks; I have done with friends during previous engagements. Some of them relate to my team members and others to me. The first role is the plant, which consists of people who are highly creative, who innovate and inv ent methods or technique. These people through innovation provide the foundation in which ideas develop in the team (Belbin 2011). These people have a character of alienating themselves from the rest of the team so that they can concentrate on their imaginative thinking. They have a personality of being introverts and are self-centered and would have strong reactions to both criticism and praise. This is because they are normally original in their ideas and being introverts, they have a weakness in communicating with other team members (Belbin 2011). In team roles, plants have an important role to play in teams because their main function is generating new ideas and techniques to assist the team to solve complex problems (select knowledge 2001). For example, in a study group that we had formed with friends in high school, we used to do group assignments as a team. One team member, Denis, was good at doing research in some of the assignment topics, but he could not explain the findin gs verbally although he wrote and analyzed them properly. In my opinion, his role in our team would fit as a plant because of his originality in presentations that helped our team to produce high quality and scored high points in our assignments. The second team role as suggested by Belbin is the resource investigators (select knowledge 2001 p. 32). They can be said to have some opposite characteristics of the plants because they are extroverts and often enthusiastic. In this role, Hogan (2007 p.65) also highlights that resource investigator are good in communicating and negotiating with people both inside and outside their teams. Notably, they are also good in accommodating ideas from other people and developing those ideas to accomplish team goals, this is due to their investigative characteristics and willingness to utilize new possibilities in those ideas. Resource Investigators have a very important function in the team as Belbin suggest, they are hence the best people to be us ed for setting up contacts with people outside the team because of their extrovert’s personality. This would, therefore, help the team to achieve their shared goals. In my teamwork experience, I would relate my personal team role as a resource investigator because; I would ensure that the team members worked cohesively.

Project plan's name Essay Example | Topics and Well Written Essays - 1250 words

Green Maps for a More Sustainable Future - Essay Example More tasks carried out by the organization are through partnering with other institution in carrying out projects such as educating the society, feeding the hungry, providing men and women with skills that are aimed at elevating their living status among others. All the projects carried out are geared towards adhering to the mission and vision of the organization. The mission of the organization is geared towards getting people to lose with the aim of impacting positive change while its vision is to catalyze a global market for information, ideas, and money that democratizes philanthropy (Globalgiving, 2015). The funding of this organization is through donors and well-wishers. Some of the organizations that the institution has partnered with are Charles Stewart Mott Foundation, Omidyar Network, USAID (Global Development Alliance), and The Rockefeller Foundation among others (Globalgiving, 2015). It is approximated that since 2002 the number of donors is roughly 421,651 and have carried out approximately 11,669 projects. The projects vary from country to country or region to region depending on situations and needs.Moreover, the projects are of different topics such as finance, education, climate change among other numerous topics ((Globalgiving, 2015). This paper seeks to address a development project being carried out by GlobalGiving on climate change Canada that is currently ongoing. Climate change is one of the major challenging issues in the society today. People have tried modifying the daily weather either by increasing or decreasing heat or temperature of the surrounding. These increase and decrease over a long period of time contribute to climate change. The threat posed by climate change has awakened international community and various governments to start setting up mitigation measures.However, in North America, response to climate change has met several challenges.These challenges are that the public have a conviction and belief